Help With Geometry Homework

[Scrapz616]

I'm completely lost on this, can someone help?
I need to find the equation of this line (a,3)(b,3).
and then I need to tell why I can't find the equation for this line (4,C)(4,D).
Can anyone help? Thanx.

[Trogdor]

text message ChaCha(242242) they answer math problems for free(other than cost of sending and recieving text message fees if you have them), trust me it works

[Red Sky]

do you know the equation for slope? It's been a little while but i think it,s (xsub2 - xsub1)/(ysub2 - ysub1). Once you have the slope, you can find the y intercept pretty easily. Also, do you have values for the exponents? If not, you'll have variables in your final answer

[moyamoya]

for 1. m= any real number. then solve for x.
2.m= any real number. then solve for y.
this is because you haven't given the gradient/ slope. they can't give you the same/no Xs for both points and the same/no Ys for both points without giving you the slope, because then the variable can be any real number. or is it the tangent of a curve and you have to derive the points after putting them in y=mx+b formula? but i'm guessing that is calculus...
go to download.com and type in equation solver. there are some pretty good ones there for free.

[Pachirisu]

Haha, it's probobly a bit late for this...

But in equation 1 you're given two points on the y-axis 3 and 3, the points on the x axis a and b can be any points on the x-axis (pick a number, any number) Because both points on the y-axis are 3 this means no matter what the x values are the line will go horizontally with an equation of y=3

The second equation is similar, except that this time you're given two points on the x-axis 4 and 4, and C/D stand for any points on the y-axis. Because the points on the x-axis are the same it means you will have a line going straight up/down with no gradient which means that the line won't have an equation....

When you have problems such as this, it's often easier to plot a graph with your x and y axes and put the given points on the graph and take it from there...