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Old 07-19-2008, 04:01 PM   #1 (permalink)
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Default Dunno how to do this math problem... help?

Lul, this probably isn't the right place in the forums to post this... so any mod move this to where it should be if there's a better spot... but anyone know how to do this problem? I have to convert 2+2sin2theta to rectangular form.. then graph.. and I have no idea where to begin.
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Old 07-22-2008, 02:27 PM   #2 (permalink)
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What do you mean, 'rectangular form?'
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Old 07-22-2008, 02:29 PM   #3 (permalink)
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Hey no fair deleting my intelligently funny post hax.
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Old 07-22-2008, 02:39 PM   #4 (permalink)
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Randy, please keep in mind that this section does fall under Serious Discussion.
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Old 07-22-2008, 02:41 PM   #5 (permalink)
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oh i didnt realize that :S sry.
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Old 07-22-2008, 02:49 PM   #6 (permalink)
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Quote:
Originally Posted by Volpe Sinatra View Post
What do you mean, 'rectangular form?'
Rectangular form as in... in terms of X and Y
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Old 07-22-2008, 03:04 PM   #7 (permalink)
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I'll assume the full equation is R = 2 + 2Θ ? Polar equation, yes?
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Old 07-23-2008, 02:17 AM   #8 (permalink)
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Quote:
Originally Posted by Volpe Sinatra View Post
I'll assume the full equation is R = 2 + 2Θ ? Polar equation, yes?
He said R=2+2sin(2theta) I believe. If I'm correct, then you can't convert it to rectangular form considering the fact that that equation is a two leafed clover. You'd need a given value for theta (a number) in order to do so.
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Last edited by Darth Camel : 07-23-2008 at 02:24 AM.



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Old 07-24-2008, 09:23 PM   #9 (permalink)
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Try playing around with the equation for a circle and use a trig identity.

(Complete guess, good luck!)



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Old 07-24-2008, 09:36 PM   #10 (permalink)
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Why do you care its the middle of summer. Summer school already ended, atleast for me it did(and no im not retarted im a freshman getting ahead, my mom made me take it).



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Old 07-25-2008, 12:03 AM   #11 (permalink)
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Quote:
Originally Posted by AceofSpades1005 View Post
Why do you care its the middle of summer. Summer school already ended, atleast for me it did(and no im not retarted im a freshman getting ahead, my mom made me take it).
It does not matter why he cares.

Polar Relationships:
x = r cos(t)
y = r sin(t)
x^2 + y^2 = r^2.

So:
sin(t) = x / r
cos(t) = y / r
sin(t) = x / sqrt(x^2 + y^2)

r = 2 + 2 sin(2t) (Assuming this is what is meant, as opposed to 2 + 2 sin^2(t))
sqrt(x^2 + y^2) = 2 + 2(sin(2t))
sqrt(x^2 + y^2) = 2 + 2(2 sin(t) + cos(t))
sqrt(x^2 + y^2) = 2 + 2(2(x / sqrt(x^2 + y^2)) + (y / sqrt(x^2 + y^2))
sqrt(x^2 + y^2) = 2 + 4x / sqrt(x^2 + y^2) + y / sqrt(x^2 + y^2)

Multiply by (x^2 + y^2)sqrt(x^2 + y^2)

(x^2 + y^2)^2 = 2((x^2 + y^2)sqrt(x^2 + y^2) + 4x(x^2 + y^2) + y(x^2 + y^2)
x^4 + y^4 + 2(x^2)(y^2) = (2x^2 + 2y^2)(x^2 + y^2)^(1/2) + 4x^3 + 4x(y^2) + (x^2)y + y^3
x^4 + y^4 - 4x^3 - y^3 + 2(x^2)(y^2) - (x^2)y - 4x(y^2) - (2x^2 + 2y^2)(x^2 + y^2)^(1/2) = 0

I think that is right...
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Old 07-30-2008, 10:27 AM   #12 (permalink)
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Quote:
Originally Posted by Netrix View Post
It does not matter why he cares.

Polar Relationships:
x = r cos(t)
y = r sin(t)
x^2 + y^2 = r^2.

So:
sin(t) = x / r
cos(t) = y / r
sin(t) = x / sqrt(x^2 + y^2)

r = 2 + 2 sin(2t) (Assuming this is what is meant, as opposed to 2 + 2 sin^2(t))
sqrt(x^2 + y^2) = 2 + 2(sin(2t))
sqrt(x^2 + y^2) = 2 + 2(2 sin(t) + cos(t))
sqrt(x^2 + y^2) = 2 + 2(2(x / sqrt(x^2 + y^2)) + (y / sqrt(x^2 + y^2))
sqrt(x^2 + y^2) = 2 + 4x / sqrt(x^2 + y^2) + y / sqrt(x^2 + y^2)

Multiply by (x^2 + y^2)sqrt(x^2 + y^2)

(x^2 + y^2)^2 = 2((x^2 + y^2)sqrt(x^2 + y^2) + 4x(x^2 + y^2) + y(x^2 + y^2)
x^4 + y^4 + 2(x^2)(y^2) = (2x^2 + 2y^2)(x^2 + y^2)^(1/2) + 4x^3 + 4x(y^2) + (x^2)y + y^3
x^4 + y^4 - 4x^3 - y^3 + 2(x^2)(y^2) - (x^2)y - 4x(y^2) - (2x^2 + 2y^2)(x^2 + y^2)^(1/2) = 0

I think that is right...
HOLY &#$!, good work!



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Old 07-30-2008, 10:51 AM   #13 (permalink)
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Quote:
Originally Posted by AceofSpades1005 View Post
HOLY &#$!, good work!
Genius, Genius, GENIUS!!!



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